Question

find three consecutive even integers whose sum is 108​

Answer 1

Answer:

Three consecutive even integers can be represented by x, x+2, x+4. The sum is 3x+6, which is equal to 108. Thus, 3x+6=108. Solving for x yields x=34.

Answer 2

Answer:

let three consecutive even numbers be x, x+2, x + 4.

According to statement

x + x + 2 + x + 4 = 108

3x + 6 = 108

3x = 102

x = 34

so numbers are 34, 36, 38