Find three consecutive even integers whose sum is 108.
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Answered by
12
x+x+1+x+2=108
3x+3=108
3x=108-3
x=105/3
finally ,the numbers are 35,36,37
3x+3=108
3x=108-3
x=105/3
finally ,the numbers are 35,36,37
Mahek456:
thanks
Answered by
4
180 is the sum
x + x + 1 + x + 2 = 108
3x + 3 = 108
3x = 108 - 3
3x = 105
x = 105/3
= 35
Hence, 35 is the value of x
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