Math, asked by Mahek456, 11 months ago

Find three consecutive even integers whose sum is 108.

Answers

Answered by Ratneshkumarsingh
12
x+x+1+x+2=108
3x+3=108
3x=108-3
x=105/3
finally ,the numbers are 35,36,37

Mahek456: thanks
Answered by Anonymous
4

\huge\bf{Answer:-}

180 is the sum

x + x + 1 + x + 2 = 108

3x + 3 = 108

3x = 108 - 3

3x = 105

x = 105/3

= 35

Hence, 35 is the value of x

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