Question

find three consecutive even integers whose sum is -12​

Answer 1

Let me help you with your query mate!

Three such even consecutive integers are -2,-4 & -6.

let's verify it!

-2+(-4)+(-6)=-2-4-6=-12.

Hence the given answer is correct.Hence three consecutive even integers summing up to -12 are -2,-4 & -6.Hope you are really helped mate!

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Answer 2

Answer:

$let \: the \: three\: consecutive \: integers \: be \: x \: \: and \: (x + 2) \: and \: (x + 4) \\ \\ according \: to \: the \: question \: x + (x + 2) + (x + 4) = - 12 \\ x + x + 2 + x + 4 = - 12 \\ 3x + 6 = - 12 \\ 3x = - 12 - 6 \\ 3x = - 18 \\ x = \frac{ - 18}{3} \\ x = - 6 \\ \\ so \: \: \: \\ x = - 6 \\ (x + 2) = - 6 + 2 = - 4 \\ (x + 4) = - 6 + 4 = - 2 \\ hence \: the \: three \: consecutive \: integers \:are \: - 6 \: and - 4 \: and \: - 2$