Question

find three consecutive even integers whose sum is 228​

Answer 1

Step-by-step explanation:

2n+2n+2+ 2n+4=228

6n=222

2n=74

no are 74 76 78

Answer 2

let the integers be x, x+1,x+2

so, x+x+1+x+2=228

3x+3=228

3x=228-3

3x=225

x= 225/3

x=75

therefore ,x+1= 76, x+2=77

hence required numbers are 75,76 and 77