Question

find three consecutive even no whose sum is 66​

Answer 1

Answer:

20, 22, 24...

hope u understand thnks u....

Answer 2

$\huge \mathtt {Question:}$

Find three consecutive even numbers whose sum is 66.

$\huge \mathtt {♡Answer:}$

Let x be one number.

The next two even consecutive numbers would be x + 2 and x + 4.

So,

x + x + 2 + x + 4 = 66

3x + 6 = 66

3x = 66 - 6 = 60

x = $\huge \frac {60}{3}$= 20

So,

x + 2 would be 20 + 2 = 22

x + 4 would be 20 + 4 = 24

Hence,

The three even consecutive numbers are 20, 22 & 24