find three consecutive even number whose sum is 246
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4
n + (n+2) + (n+4) = 246
3n = 240
n = 80
so numbers are 80,82,84
3n = 240
n = 80
so numbers are 80,82,84
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Answered by
1
Let the 3 consecutive even no. be x , x+2 , x+4
Then , x+x+2+x+4= 246
3x+6=246
3x =246-6
x =240/3
=80
x+2=82 , x+4=84
Then , x+x+2+x+4= 246
3x+6=246
3x =246-6
x =240/3
=80
x+2=82 , x+4=84
why we take even numbers be x,(x+2),(x+4)
bcoz gaping will be at even interval , otherwise it won't give the even no.'s sum
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