Question

Find three consecutive even numbers such that the sum of first and third is 40.​

Answer 1

Answer:

$\bigstar{\bold{The\:numbers\:are\:18,\:20,\:22}}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• The 3 numbers consecutive even numbers
• Sum of first and third number is 40

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• The 3 numbers

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Let the first number be x

→ Let the second number be x + 2

→ Let the third number be x + 2 + 2 = x + 4

→ By given,

  x + x + 4 = 40

  2x + 4 = 40

  2x = 40 - 4

  2x = 36

    x = 36/2

    x = 18

→ Hence the first number = x = 18

  Second number = x + 2 = 18 + 2 = 20

  Third number = x + 4 = 22

$\boxed{\bold{The\:numbers\:are\:18,\:20,\:22}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The sum of an even number and odd number is always an odd number.

→ The sum of two even numbers is always an even number.

→ The sum of two odd numbers is always an even number.

Answer 2

The numbers are 18 , 20 and 22

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