Question

find three consecutive even numbers such that the sum of twice the least number and thrice the greatest number is 622

Answer 1

hey mate
here's the solution

Answer 2

$\large\bold{\boxed{Solution}}$

We know that consecutive numbers differ by 1 and consecutive even numbers differ by 2.

So we may assume the following as the required even numbers,

x, ( x + 2 ) and ( x + 4 )

Now on reading the question carefully we can form the following equation which in turn would help us to find the required answer.

2x + 3 ( x + 4 ) = 622
2x + 3x + 12 = 622
5x = 622 - 12
5x = 610
x = 610 / 5
x = 122

Hence the required consecutive even numbers are as follows,

122, ( 122 + 2 ) and ( 122 + 4 )
122, 124 and 126