find three consecutive even numbers such that the sum of the first and the last numbers exceeds the second number by 10
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Step-by-step explanation:
let the three consecutive numbers be x,
x + 2 ,x + 4
(x+x+4) -(x+2)=10
(2x+4)-x-2=10
x+2=10
x=10-2
x=8
x+2=10
x+4=12
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