Question

find three consecutive even numbers such that the sum of the first and the last number exceeds the second number by 10

Answer 1

↑ Here is your answer ↓
_____________________________________________________________
_____________________________________________________________

These even numbers are in A.P,

They are (a - d), (a), (a + d)

$(a - d) + (a+d) = a+ 10$

$a - d + a + d = a + 10$

'd' get cancelled,

$2a = a + 10$

$a = 10$

For consecutive even numbers, 'd' = 2

So, the numbers are:

$a-d = 10-2 = 8$

$a = 10$

$a + d = 10+2 = 12$

Answer 2

refer the pic..
hope it'll help..
mark it as brainliest..