Question

Find three consecutive even numbers such that the
sum of the first and the last number exceeds the
second number by 18.​

Answer 1

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Answer 2

Answer:

16, 18 and 20

Step-by-step explanation:

Let the three consecutive even numbers as (x-2),  x, (x+2)

According to question => (x-2) + (x+2) = x + 18

=> x-2+x+2 = x +18       (Solving Brackets)

=> 2x = x + 18

=> 2x - x = 18                 ( Transposing x to LHS)

=> x = 18    

So, other numbers are=  18-2 => 16 and 18+2 => 20