Question

Find three consecutive even numbers such that the sum of the first and the last numbers exceeds the middle number by 20.

Answer 1

Let the numbers be a, a +2 and a + 4

According to question,

a + a + 4 = a + 2 + 20

=> 2a + 4 = a + 22

=> 2a - a = 22 - 4

=> a = 18

First number = 18

Second number = 18+2 = 20

Third number = 18 + 4 = 22

Answer 2

Hey dear friend here's ur answer..
Let the numbers be x, x+2, and x+4
So x+x+4 =x+2+20
So 2x+4 =x+22
So x=18..
So the ist no. Is 18
2nd is 18+2 =20
3rd is 18+4 =22