Find three consecutive even numbers such that the sum of the first and the third is 40
Answers
Answered by
6
x, x+2,x+4 are numbers
x+x+4=40
2x+4=40
2x=40-4
2x=36
x=36/2
x=18
x+2=18+2=20
x+4=18+4=22
numbers are
18,20,22
x+x+4=40
2x+4=40
2x=40-4
2x=36
x=36/2
x=18
x+2=18+2=20
x+4=18+4=22
numbers are
18,20,22
Answered by
5
let the three consecutive even numbers are
x+2 , x +4 , x +6
given sum = 40
(x+2)+(x+6) = 40
2x+ 8= 40
2x = 40 - 8
x = 32/2
x = 16.
x+2 = 16 +2 = 18
x + 4 = 16 + 4 = 20
x + 6 = 16 + 6 = 22
hence three consecutive even numbers are 18, 20 , 22
x+2 , x +4 , x +6
given sum = 40
(x+2)+(x+6) = 40
2x+ 8= 40
2x = 40 - 8
x = 32/2
x = 16.
x+2 = 16 +2 = 18
x + 4 = 16 + 4 = 20
x + 6 = 16 + 6 = 22
hence three consecutive even numbers are 18, 20 , 22
eldrickdalbotpej8k8:
superb.. thanks a lot
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