Question

find three consecutive even numbers such that the sum of the first and the last numbers exceed s the middle number by 20 .

Answer 1

$<b>$HEY MATE HERE IS YOUR ANSWER

$\rule {168} {2}$

Let the numbers be (x - 2), (x) and (x+2)

➡️ Sum of the first and last number exceeds middle number by 20.

=> (x - 2)+(x+2)=x+20

=> x - 2 + x + 2 = x + 20

=>2x = x + 20

➡️ 2x - x = 20

➡️ x = 20

Now,

First number :- x - 2

➡️ 20 - 2 =

➡️ 18

Second number :- x = 20

Third number :- x + 2

➡️ 20 + 2

➡️ 22

$\rule {168} {2}$

Hope it will help you

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