find three consecutive even numbers such that the sum of the first and the last numbers exceed s the middle number by 20 .
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Let the number be (x - 2), (x) and (x +2).
The sum of the first and last number exceeds middle number by 20.
=>(x - 2) +(x +2) =x +20
=> 2x = x + 20
=> 2x - x = 20
➡️ x= 20
Now,
First number :- x - 2
➡️ 20 - 2
➡️ 18
Second number :- x
➡️ 20
Third number :- x + 2
➡️ 20 + 2
➡️ 22
Hope it will help you
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Let the number be (x - 2), (x) and (x +2).
The sum of the first and last number exceeds middle number by 20.
=>(x - 2) +(x +2) =x +20
=> 2x = x + 20
=> 2x - x = 20
➡️ x= 20
Now,
First number :- x - 2
➡️ 20 - 2
➡️ 18
Second number :- x
➡️ 20
Third number :- x + 2
➡️ 20 + 2
➡️ 22
Hope it will help you
@thanksforquestion
@bebrainly
@warm regards
Ansh as ans81
@mark as brainliest
#be brainly
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