Question

Find three consecutive even numbers whose sum equals 708.​

Answer 1

Answer:

Therefore The number are 235, 236 and 237.

Answer 2

Given: The sum of three consecutive even numbers is$708$.​

We have to find the three consecutive even numbers.

We are solving in the following way:

We have,

The sum of three consecutive even numbers is$708$.

Let assume the three consecutive even numbers are$x,(x+2),(x+4)$.

So, from the above statement we can write:

$x+(x+2)+(x+4)=708$

Solving the above equation further we get,

$=>x+x+2+x+4=708\\=>3x+6=708\\=>3x=708-6\\=>3x=702\\\\=>x=\frac{702}{3} \\\\=>x=234$

So, the three consecutive even numbers will be:

$=>x=234\\=>x+2=>234+2=>236\\=>x+4=>234+4=>238$

Hence, the three consecutive even numbers are$234,236,\ and\ 238$.