Find three consecutive even numbers whose sum is 108.
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Answer:
let x is an even number
then x,x+2,x+4 are three even consecutive number
so,x+x+2+x+4=108
3x+6=108
3x=108-6
3×=102
×=102/3=34
so, x= 34
x+2= 36
x+3=
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