Question

Find three consecutive even numbers
whose sum is 144.​

Answer 1

Answer:

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Step-by-step explanation:

Let the three consecutive even numbers be (n -2), n, and (n +2).

=> n - 2 + n + n + 2 = 144

=> 3 n = 144

=> n = 4 8,

So the three consecutive even numbers ars 46, 48 and 50

Answer 2

Answer :-

• The three consecutive even numbers are 46, 48 and 50.

To find :-

• The three consecutive even numbers whose sum is 144.

Step-by-step explanation :-

• In this question, it has been given that the sum of three consecutive even numbers is 144 and we have to find these numbers. We know that even numbers are divisible by 2 and they differ by 2 as well. Let's use this knowledge to find our answer.

Calculations :-

• Let the first number be x.

• Then the second number will be (x + 2) and the third number will be (x + 4).

• Now, the sum of these numbers is 144.

$\bf\implies x + (x + 2) + (x + 4) = 144$

Removing the brackets,

$\bf \implies x + x + 2 + x + 4 = 144$

On adding all the variables and constants,

$\bf \implies 3x + 6 = 144$

Transposing 6 from LHS to RHS, changing it's sign,

$\bf \implies 3x = 144 - 6$

On simplifying,

$\bf \implies 3x = 138$

Transposing 3 from LHS to RHS, changing it's sign,

$\bf \implies x = \dfrac{138}{3}$

Dividing 138 by 3,

$\bf\implies x = 46.$

• The value of x is 46.

Hence, all the numbers are as follows :-

$\rm x = 46.$

$\rm x + 2 = 46 + 2 = 48.$

$\rm x + 4 = 46 + 4 = 50.$

• Hence, the numbers are 46, 48 and 50.