find three consecutive even numbers whose sum is 246
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Hey mate, Here is your answer ↓
Let the first no. be x
2nd no. be x+2
3rd no. be x+4
Sum of three consecutive even numbers = 246.
A/Q,
→x + (x+2) + (x+4) = 246
→ 3x + 6 = 246
→ 3x = 246 - 6
→ 3x = 240
→ x = 240/3
→ x = 80.
Hence, The 1st no. is 80
2nd no. is 80+2 = 82 and
3rd no. is 80+4 = 84.
Hope it helps you (^•^)
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