Find three consecutive even numbers whose sum is 252.
Answers
Answer:
Let the smallest of three consecutive number be X , therefore other two consecutive numbers will be X+1 and X+2
As per the statement, the sum of these consecutive numbers is 252, means
X + (X+1) + (X+2) = 252
X+X+1+X+2=252
3X + 3 = 252
3X = 252–3
3X=249
X=249/3
X = 83
Thus the smallest consecutive number is 83
Therefore other two consecutive numbers are
X+1
83+1=84 and
X+2
83+2=85
Thus the three consecutive numbers are 83, 84 and 85
Answer:
The 3 numbers are 82, 84 and 86
Step-by-step explanation:
Let the smallest number of those consecutive numbers be x.
So, the numbers are x, (x + 2), (x + 4)
According to the question, the equation will be formed like this:
x + x + 2 + x + 4 = 252
3x + 6 = 252
3x = 246
x = 82
Thus, x = 82, x + 2 = 84, x + 6 = 86
Hence those 3 numbers are 82, 84 and 86.
Hence solved.