find three consecutive even numbers whose sum is 48
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Answered by
1
Answer:
Let the First number be x.
Let the second number be x + 1.
Let the third number be x + 2.
So, x + (x + 1) + (x +2) = 48
3x + 3 = 48
3x = 48 - 3
3x = 45
x = 45
3
x = 15
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Answered by
2
answer:
15,16,17,
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