Find three consecutive even numbers whose Sum is 48
Answers
Answered by
10
Let the numbers be x,x+2,x+4
By the problem,x+x+2+x+4=48
3x+6=48
3x=42
x=14
Therefore the numbers are 14,16,18.
By the problem,x+x+2+x+4=48
3x+6=48
3x=42
x=14
Therefore the numbers are 14,16,18.
Answered by
5
consecutive means following no's.
lets 'x' be the an unknown even no..so x, x+2 and x+4 should be equal to 48. yes?
so x+x+2+x+4=48
=> 3x+6=48
=> 3x=48-6 (no.6 is taken on the other side and becomes negative)
=>3x=42
=> x=42/ 3 ( dividing 42 by 3.)
therefore, x=14 ...u can also check this answer
lets 'x' be the an unknown even no..so x, x+2 and x+4 should be equal to 48. yes?
so x+x+2+x+4=48
=> 3x+6=48
=> 3x=48-6 (no.6 is taken on the other side and becomes negative)
=>3x=42
=> x=42/ 3 ( dividing 42 by 3.)
therefore, x=14 ...u can also check this answer
Similar questions