find three consecutive even numbers whose sum is 66
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Answered by
33
Let the smallest number be x
The other 2 numbers are (x + 2) and (x + 4)
Their sum is 66:
x + (x + 2) + (x + 4) = 66
x + x + 2 + x + 4 = 66
3x + 6 = 66
3x = 60
x = 20
Find the numbers:
smallest number = x = 20
2nd number = x + 2 = 20 + 2 = 22
3rd number = x + 4 = 20 + 4 = 24
Answer: The numbers are 20, 22 and 24
Senthilkumar06051977:
I have one doubt
Answered by
9
Answer:
20 , 22 , 24 this is only the answer
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