find three consecutive even numbers whose sum is 96
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Answered by
7
Hey mate!
Here is your answer > >
Let three consecutive even numbers be x, x+2 and x+4
According to question
x+x+2+x+4=96
3x+6=96
3x=96-6
3x=90
x=90/3
x=30
First number=x=30
Second number=x+2=30+2=32
Third number=x+4=30+4=34
Hope it helps!
Thankyou ☆ ☆
Here is your answer > >
Let three consecutive even numbers be x, x+2 and x+4
According to question
x+x+2+x+4=96
3x+6=96
3x=96-6
3x=90
x=90/3
x=30
First number=x=30
Second number=x+2=30+2=32
Third number=x+4=30+4=34
Hope it helps!
Thankyou ☆ ☆
Answered by
3
let the even no be x
2nd- x+2
3rd- x+4
x+x+2+x+4=96
3x+6=96
3x=96-6
3x=90
x=90/3
x=30
hence the three consecutive no be 30, 32 & 34
2nd- x+2
3rd- x+4
x+x+2+x+4=96
3x+6=96
3x=96-6
3x=90
x=90/3
x=30
hence the three consecutive no be 30, 32 & 34
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