Question

find three consecutive even numders whose sum is 66​

Answer 1

Step-by-step explanation:

Let the smallest numbers be X

The other 2 numbers are (x+2) and (x+4)

Their sum is 66:

x+(x+2)+(x+4)=66x+x+2+x+4=663x+6=663x=60x=20

Then,

We get smallest number=x=20

2nd number=x+2=20+2=22

3rd number=x+4=20+4=24

Answer 2

20,22 and 24 r the three consecutive even numbers whose sum is 66. We can prove it also by adding them

20+22+24= 66