Find three consecutive integers such that the square of the first increased by the product of the other two gives 154.
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Step-by-step explanation:
let the integers be x , x+1 ,x+2
ATQ: x² + (x+1)× (x+2) = 54
x² + x² + 2x +x +2 =54
2x² +3x +2-54 =0
2x²+ 3x -52 =0
2x² +
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