Question

Find three consecutive integers such that the sum of the first, twice the second, and
three times the third is − 76.

Answer 1

Step-by-step explanation:

What are three consecutive integers such that the sum of the first twice the second and three times the third is -76? - Quora. the 3 numbers are -14, -13, and -12. -14 + -26 + -36 = -76, everything works!

Answer 2

The three consecutive integers are -14,-13 and -12 such that they follow the given condition.

Given

Three integers are consecutive

The sum of the first , twice the second and 3 times the third is -76

To find:

The three integers

Solution:

Let the first integer be "x".

Now the second integer should be  $x+1$ and the third integer is $x+2$ .

Now we will use the given condition to form a linear equation in x:

$x+2(x+1)+3(x+2)=-76$

Now we have to solve the above equation to calculate the value of x and we will get the required integers.

$x+2(x+1)+3(x+2)=-76\\\\or, 6x+6=-76\\\\or, 6x = -84\\\\or, x =-14$

Thereofre the first integer is -14.

The second integer = $x+1 =-14+1 =-13$

The third integer is : $x+2 =-14+2 =-12$

Therefore the three integers such that the sum of the first,twice the second and three timers the third is -76 .

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