Find three consecutive integers such that the sum of twice the first, the second and
thrice the third is 367.
pls give explanation as well
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Answered by
4
Answer:
Step-by-step explanation:let the no. = x-1, x , x+1
A.T.Q
2( x-1) + 3x + 4( x+1) =146
2x -2 + 3x +4x+4 = 146
9x + 2 = 146
9x = 146-2
x = 144/9
x= 16
hence, no. are 15, 16, 17
Answered by
1
Answer:
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