Question

FIND THREE CONSECUTIVE INTEGERS SUCH THAT THIRD IS ONE AND A HALF TIMES THE FIRST

Answer 1

let the three consecutive integers be,
x-1 , x , x+1
according to the question,
x-1 = (x+1)3/2
2 (x-1) = 3 (x+1)
2x-2 = 3x+3
2x-3x = 3+2
-x = 5
x = -5
putting the value of x in the three consecutive integers we get
-6 , -5 , -4
Ans: -6 , -5 ,-4

Answer 2

Let the three consecutive integers be x - 1, x, x + 1.

Given that Third is one and a half times the first.

= > (x + 1) = 1 1/2(x - 1)

= > (x + 1) = (3/2) (x - 1)

= > (x + 1) = 3(x - 1)/2

= > 2(x + 1) = 3(x - 1)

= > 2x + 2 = 3x - 3

= > 2x = 3x - 5

= > x = 5.


Now,

x - 1 = 5 - 1 = 4

x + 1 = 5 + 1 = 6.


Therefore, the three consecutive integers are 4,5,6.


Hope this helps!