find three consecutive integers such that third is one and a half times the first
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Let the three consecutive integers be x - 1, x, x + 1.
Given that Third is one and a half times
the first.
=> (x + 1) = 1 1/2(x - 1)
=> (x + 1) = (3/2) (x - 1)
=> (x + 1) = 3(x - 1)/2
=> 2(x + 1) = 3(x - 1)
=> 2x + 2 = 3x - 3
=> 2x = 3x - 5
=> x = 5.
Now,
x-1= 5-1 = 4
x+1=5+1 = 6.
Therefore, the three consecutive integers are 4,5,6.
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