Math, asked by azizfatma7892, 11 hours ago

find three consecutive integers such that third is one and a half times the first​

Answers

Answered by shreya882001
1

Answer:

Let the three consecutive integers be x - 1, x, x + 1.

Given that Third is one and a half times

the first.

=> (x + 1) = 1 1/2(x - 1)

=> (x + 1) = (3/2) (x - 1)

=> (x + 1) = 3(x - 1)/2

=> 2(x + 1) = 3(x - 1)

=> 2x + 2 = 3x - 3

=> 2x = 3x - 5

=> x = 5.

Now,

x-1= 5-1 = 4

x+1=5+1 = 6.

Therefore, the three consecutive integers are 4,5,6.

Answered by uzmanoor304
1

Step-by-step explanation:

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