Question

Find three consecutive integers such that twice the sum of the first two is 11 more then three times the largest

Answer 1

here it is ....plz mark as brainliest

Answer 2

Hey mate here is your answer::::



♥♥♥♥♥♥♥♥♥♥♥♥



According to the question ::::




Let the first integer be X

Let the second integer be X+1

Let the third integer be X+2



2(X+X+1) =11+3(X+2)

2(2x+1)=11+3x+6

4x+1=17+3x

4x-3x=17-1

X=16




•••••••••••••••••THEREFORE•••••••••••••••••



The first integer = 16

The second integer =17

The third integer =18


•••••••••••$THANKS$••••••••••••••


~♥~♥~♥~♥~♥~♥~♥~♥~♥~♥

$be \: brainly$