Find three consecutive integers whose product is equal to their sum.
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Let x be an one of the those consecutive integer, then integers would be. x-1, x, x+1
then, ATQ,
x + (x+1) + (x+2) = x(x-1)(x+1)
3x = x^3 - x
x(x^2 - 4) = 0
So, x= 0,2,-2
so, the answer are three sets
1) -1,0,1
2)-3,-2,-1
3)1,2,3
then, ATQ,
x + (x+1) + (x+2) = x(x-1)(x+1)
3x = x^3 - x
x(x^2 - 4) = 0
So, x= 0,2,-2
so, the answer are three sets
1) -1,0,1
2)-3,-2,-1
3)1,2,3
MrMk:
should i upload method?
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