Question

Find three consecutive integers whose sum is 11 more than twice the greatest of the three integers.

Answer 1

Step-by-step explanation:

combine like terms and distribute the 2 on the right

3X + 3=11+2X+4

3X-2X+3-3=11+2X-2X+4-3

X=11+4-3

X=12

Integers are 12,13 and 14

PROOF:

12+13+14=39

11+2(12+2)=11+2(14)=11+28=39..