Question

Find three consecutive integers whose sum is 63.​

Answer 1

Answer:

let one of the number is x then other two are x+1,x+2

Step-by-step explanation:

acc. to question

x+x+1+x+2=63

3x+3=63

3x=60

x=60/3

x=20

Then the consecutive integers are 20,21&22

Answer 2

Let the three consecutive integers be (x-1), x, (x+1)

Now,

x-1+x+x+1=63

x+x+x+1-1=63

3x=63

x=63/3

x=21

So, the integers are,. x-1=21-1=20

x=21

x+1=21+1=22

Hence, the three consecutive integers are 20, 21 and 22.