Find three consecutive integers whose sum is 96.
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Given
the sum of three consecutive integers is 96.
To Find
three consecutive integers
Let us assume that the first integer be 'x'
second integer be 'x+1'
And the third integer be 'x+2'
Now, according to the question
Add all the three integers
=>x+x+1+x+2=96
=>3x+3=96
=>3x= 96-3
=>3x=93
=>x= 93/3
=>x= 31
Therefore ,x= 31
let's finding the Integers
first integer is 'x'= 31
second integer is 'x+1'= 31+1=32
third integer is 'x+2'= 31+2= 33
Check:
Sum of all three consecutive integers is 96
=>31+32+33
= 96
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