Math, asked by kishu6331, 9 months ago

find three consecutive largest positive integers such that the sum of one - third of first and one - fourth of second and one - fifth of third is at most 20.​

Answers

Answered by 001REBEL
3

Answer:

Let the numbers be x - 1, x, x + 1 1/3(x - 1) × 20 + 1/4(x) × 15 + 1/5(x + 1) × 12≤ 20 20x - 20 + 15x + 12x + 2/60≤ 20 47x - 18≤ 1200 47x≤ 1218

Answered by Anonymous
2

find three consecutive largest positive integers such that the sum of one - third of first and one - fourth of second and one - fifth of third is at most 20.

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