Question

Find three consecutive multiples of 11, whose sum is 363.

Answer 1

Suppose, three numbers are 11x,11x+11 & 11x+ 22
As per question, 11x+11x+11+11x+22=363
or, 33x=363 - 33=330
or, x=330/33=10
So 1st multiple of 11=110
2nd multiple=121
3rd number=132

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.