find three consecutive natural number such that the sum of the first and second is 18 more than the third
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Step-by-step explanation:
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4
Answer:
The three consecutive numbers are 19, 20, 21.
Step-by-step explanation:
Let the numbers be x, (x+1), (x+2).
As the sum first and second number is equal to the sum of 18 and the third number.
x +(x+1) = (x+2) + 18
2x + 1 = x + 20
x = 19
x+1 = 20
x+2 = 21.
:) Thank You . . !
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