find three consecutive natural number such that the sum of the first and the second is 30 more than the third number
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let 3 consecutive natural number be
X,X+1,X+2
given that X+X+1=30+X+2
2x+1 =32+X
2x-x=32-1
X=31
therefore three consecutive natural number are
31 ,32, 33
anishgujjar48:
ur answer is wrong
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