Find three consecutive natural numbers such that the sum of and second is 15 more than the third
Answers
Answered by
1
Answer:
16,17,18
Step-by-step explanation:
Required three consecutive natural numbers are 16,17 and 18
Let x,(x+1),(x+2) are three consecutive natural numbers.
According to the question
The sum of the first and second is 15 more than the third number.
=> x+(x+1)-(x+2)=15
=> x+x+1-x-2=15
=> x-1=15
=> x = 15+1
=> x = 16
Then
Required three consecutive natural numbers are :
x = 16,
x+1 = 16+1 = 17,
x+2 = 16+2 = 18 All are the answers hope it helps you
Answered by
2
Answer
Let numbers = x, x+1, x+2
x + x + 1 = x + 2 + 15
=> 2x = 17 + x - 1
=> x = 16
Numbers = 16, 17, 18
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