Math, asked by neev19, 1 year ago

Find three consecutive natural numbers such that the sum of and second is 15 more than the third

Answers

Answered by Anonymous
1

Answer:

16,17,18

Step-by-step explanation:

Required three consecutive natural numbers are 16,17 and 18

Let x,(x+1),(x+2) are three consecutive natural numbers.

According to the question

The sum of the first and second is 15 more than the third number.

=> x+(x+1)-(x+2)=15

=> x+x+1-x-2=15

=> x-1=15

=> x = 15+1

=> x = 16

Then

Required three consecutive natural numbers are :

x = 16,

x+1 = 16+1 = 17,

x+2 = 16+2 = 18 All are the answers hope it helps you

Answered by Anonymous
2

Answer

Let numbers = x, x+1, x+2

x + x + 1 = x + 2 + 15

=> 2x = 17 + x - 1

=> x = 16

Numbers = 16, 17, 18

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