Question

Find three consecutive natural numbers such that the sum of the first and the second
is 15 more than the third.​

Answer 1

Step-by-step explanation:

Let the first consecutive number = x,

Second consecutive number = x + 1

and Third consecutive number = x + 2

According to the condition,

x+x+1=15+x+2x+x+1=15+x+2

⇒2x+1=17+x⇒2x+1=17+x

⇒2x-x=17-1⇒2x−x=17−1

⇒x=16⇒x=16

∴ The first natural number = x = 16

Second natural number = x+1 = 16+1 = 17

Third natural number = x +2 = 16 + 2=18

Hence, the three consecutive natural numbers are 16, 17 and 18.

Answer 2

Given:-

• The sum of the first and the second is 15 more than the third.

To Find:-

• Find three consecutive natural numbers.

Concept:-

• Firstly let's understand the concept.We should take x as the unknown number.Take it's consecutives by adding +1, +2 like that.Substitute the values by making an equation and equate it.

Solution:-

Let the first consecutive number = x

Second consecutive number = x + 1

Third consecutive number = x + 2

According to the Question we have,

⇒x + x + 1 = 15 + x + 2

⇒2x + 1 = 17 + x

⇒2x - x = 17 - 1

⇒x = 16

Therefore,

⇒The First natural number is 16.

We got the value of x as 16.

Now,Substitute the value of x.

⇒x + 1

⇒16 + 1 = 17

Hence,

⇒The Second natural number is 17.

⇒x + 2

⇒16 + 2 = 18

Hence,

⇒The Third natural number is 18.

Therefore,

⇒The three consecutive natural numbers are 16,17 and 18.