Question

Find three consecutive natural numbers such that the sum of the first and second is 39 more than the third number.

Answer 1

Let the smallest number be x.
Then the next two natural numbers are x+1 and x +2
You are told



So the numbers are 40, 41 a nd 42.
Check your answer, Is 40+41 = 42+39?? 
Answer by mananth(15190)   (Show Source): You can put this solution on YOUR website!
find three consecutive natural numbers such that the sum of the first and the second is 39 more than the third number.
...
x,x+1,x+2
...
x+x+1=x+2+39
2x+1=x+41
2x-x=41-1
x=40
...
40,41,42
...

Answer 2

Let the three numbers be: x-1, x and x+1.

-Therefore, x-1 + x + x+1 =3x = 39

-Hence x, the middle number is 13.

-The other two numbers are 12 and 14.: