Question

find three consecutive natural numbers such that the sum of the first and the second is 39more than the third number.
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Answer 1

Answer:

The three consecutive natural number are 40,41,42

Step-by-step explanation:

Let the three consecutive natural number are n, n+1, n+2

Now the sum of the first and second is = n+(n+1) = 2n+1

Now by given condition,

(2n+1) -39 = n+2

=> 2n+1-39=n+2

=> 2n-n=2+39-1=40

=> n =40

So the three consecutive natural number are 40, 40+1, 40+2

i,e. 40,41,42