Find three consecutive natural numbers such that the sum of the first and second is 39 more than the third no.
Answers
Answered by
9
Plz mark me as a brainlist
let the smallest no. Be x
X + X+1 = X + 2 + 39
2X +1 = X + 41
2X- X = 41 - 1
X = 40
X + 1 = 40
40 + 1 = 41
X+2 = 40
40 + 2 =42
...........................................
I hope that it will help you. ..!
let the smallest no. Be x
X + X+1 = X + 2 + 39
2X +1 = X + 41
2X- X = 41 - 1
X = 40
X + 1 = 40
40 + 1 = 41
X+2 = 40
40 + 2 =42
...........................................
I hope that it will help you. ..!
Similar questions