Question

find three consecutive no.s whose sum is 96

Answer 1

Let the first number be a

Second number = a +1

Third number = a +2

According to question

a + a+1 + a + 2 = 96

=> 3a + 3 = 96

=> 3a = 93

=> a = 31

First number = 31

Second number = 32

Third number = 33

Answer 2

Let the no. Be x, x+1+x+2
Hope it helped u friend
See the solution in the pic