Find three consecutive no. such that if they are divided by 10,17 and 26 respectively the sum of their quotients will be 10
(Hint: Let the consecutive no. =x,x+1,x+2,then x/10 + x + 1/17 + x+2/26 = 10
Answers
Answered by
0
Answer:
m kyu btau khud solve kar lo
gotted
Similar questions