Question

find three consecutive number if 3 times number the middle number is greater than the sum of the first and the last number by 176

Answer 1

Let the three consecutive numbers be x, x + 1 and x + 2


Now, its said that, 3 times number the middle term, so the middle number be 3(x + 1)

Also said, 3 times number the middle number is greater than the sum of the first and the last number = x + 2



A/q,

3(x + 1) = x + x + 2 + 176

3x + 1 = 2x + 178

3x - 2x = 178 + 1

x = 179



$\star{}$ 1st number => x => 179


$\star{}$ 2nd number => x + 1 => 179 + 1 => 180


$\star{}$ 3rd number => x + 2 => 179 + 2 = 181





$\therefore{}$ The numbers are 179, 180 and 181

Answer 2

Here is your solution

Let,
The three consecutive numbers be x, x + 1 and x + 2


Now,

A/q

its said that, 3 times number the middle term, so the middle number be 3(x + 1) 

Also said, 3 times number the middle number is greater than the sum of the first and the last number = x + 2


A/q,

3(x + 1) = x + x + 2 + 176

3x + 1 = 2x + 178

3x - 2x = 178 + 1

x = 179



 1st number => x => 179


2nd number => x + 1 => 179 + 1 => 180


3rd number => x + 2 => 179 + 2 = 181


 The numbers are 179, 180 and 181