find three consecutive number if three times the middle number is greater than the sum of the first and last number by 176
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let the three consecutive numbers be x ;x + 1 ,X + 2
according to the question ;
3 ( X + 1 )- (X + X + 2) is equal to 176
3x+3-(2x +2)=176
3 X + 3 -2x -2= 176
X+1=176
X=175
X+1=176
X+2=177
according to the question ;
3 ( X + 1 )- (X + X + 2) is equal to 176
3x+3-(2x +2)=176
3 X + 3 -2x -2= 176
X+1=176
X=175
X+1=176
X+2=177
Answered by
1
ANSWER:
ANSWER:175,176,177
ANSWER:175,176,177 STEP BY STEP:
ANSWER:175,176,177 STEP BY STEP:let the first number be x
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+2
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=176
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=176
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=176
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176x+1=176
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176x+1=176x=176-1
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176x+1=176x=176-1x=175
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176x+1=176x=176-1x=175first number is 175
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176x+1=176x=176-1x=175first number is 175second number is x+1=175+1=176
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176x+1=176x=176-1x=175first number is 175second number is x+1=175+1=176third number is x+2=175+2=177
ANSWER:175,176,177 STEP BY STEP:let the first number be xlet the second number be x+1let the third number be x+23(x+1)-(x+x+2)=1763x+3-(2x+2)=1763x+3-2x-2=1763x-2x+3-2=176x+1=176x=176-1x=175first number is 175second number is x+1=175+1=176third number is x+2=175+2=177thus, the three consecutive number are 175,176,177 respectively
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