find three. consecutive number such tha 7 times the smallest number is equal to 3 times of som of other 2
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let the three consecutive numbers be x, x+1, x+2.
7x = 3{(x+1)+(x+2)}
7x = 3{2x+3}
7x = 6x +9
7x-6x=9
x = 9
therefore, three consecutive numbers are:
x = 9
x+1 = 10
x+2 = 11
7x = 3{(x+1)+(x+2)}
7x = 3{2x+3}
7x = 6x +9
7x-6x=9
x = 9
therefore, three consecutive numbers are:
x = 9
x+1 = 10
x+2 = 11
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