Question

find three consecutive number such that the sum of the second and the third number exceeds the first by 14

Answer 1

ket x be the first no.

2nd = x+1
3rd = x+2

x+1+x+2-14=x
2x+3-14=x
2x-x=14-3
x=11

1st=11
2nd=12
3rd=13

12+13-14=11
25-14=11
11=11

verified